3x^2-216=63x

Solution for 3x^2-216=63x equation:

3x^2-216=63x

We move all terms to the left:

3x^2-216-(63x)=0

a = 3; b = -63; c = -216;
Δ = b2-4ac
Δ = -632-4·3·(-216)
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6561}=81$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-81}{2*3}=\frac{-18}{6}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+81}{2*3}=\frac{144}{6}
=24
$